Test

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všimnúť,

ť

ť

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google street

cbll=lat,lng; z=zoom; cbp=x,yaw,x,zoom,pitch

http://maps.google.com/maps?q=Karel+Doormanhof+45,+Deelgemeente+Centrum,+Rotterdam,+Nederland&hl=en&ll=51.918345,4.474354&spn=0.008444,0.01929&sll=48.145329,17.111217&sspn=0.001142,0.002411&oq=Karel+Doormanhof+45&hnear=Karel+Doormanhof+45,+Deelgemeente+Centrum,+Rotterdam,+Zuid-Holland,+The+Netherlands&t=m&z=16&layer=c&cbll=51.918247,4.474387&panoid=CYD94kZwgx3ql_j0N_0XRA&cbp=12,47.13,,0,1.99

log

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test

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<wikitex refresh dpi="144"> \section*{Education} \begin{itemize} \item M.A. Media Design and Communication: Networked Media, Piet Zwart Institute, Willem de Kooning Academy, Rotterdam University, Netherlands, 2010--2012. \item M.A. Information Technologies, Faculty of Economic Informatics, Economic University of Bratislava, Slovakia, 1997--2002. \begin{itemize} \item \textit{Dissertation:} Electronic Business (Online Market in the Mirror of Chaos Theory). \end{itemize} \item Mass Media Communication, Faculty of Mass Media Communication, University of Cyril and Method in Trnava, Slovakia, 1999--2001. \end{itemize} </wikitex>

<wikitex> Let $Q$ be any finite set, and $\mathcal B=2^Q$ be the collection of the subsets of $Q$. Let $f:\mathcal B\rightarrow \mathbb R$ be a function assigning real numbers to the subsets of $Q$ and suppose $f$ satisfies the following conditions:

(i) $f(A)\ge 0$ for all $A\subseteq Q$, $f(\emptyset)=0$,
(ii) $f$ is monotone, i.e. if $A\subseteq B\subseteq Q$ then $f(A)\le f(B)$,
(iii) $f$ is submodular, i.e. if $A$ and $B$ are different subsets of $Q$ then
     $$f(A)+f(B)\ge f(A\cap B) + f(A\cup B).\eqno{(2)}$$

</wikitex>


<wikitex> <math>\frac{1}{\displaystyle1+\frac{1}{\displaystyle 1+\sqrt{5}}}</math> </wikitex>

html5 video